Από την ευθεία φόρτου ac βρίσκεις τις ακραίες τιμές της Vce (δηλ 0,Vceq,Vcemax) μετα στην εξίσωση
Vc= Ie*Re1 + Vce => Vc = (β/β+1 )*Ic*Re1 +Vce αντικαθιστάς τα παραπάνω Vce και τα αντίστοιχα Ic και εχει; βρει τις ακραίες τιμές της Vc και τη Vcq μετά Dvmax=min(Vcmax-Vcq,Vcq-Vcmin) . To DVmax που δίνει ο κοντολέοντας ειναι *2 (δηλ p-p) στον τύπο του Plmax πρέπει κανονικά να το βάλεις δια 2. Για το Αο από τους τύπους ενίσχυσης Ηλεκτρονική ΙΙ.
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